Chemistry, asked by Tulsirani100, 1 year ago

The total energy of an electron in an excited state is E what is its K.E with proper sign
a)-2E
b)+2E
c)-E
d)+E

Answers

Answered by itzIntrovert
20
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Your answer is option (c) -E

★ TOTAL ENERGY = K.E + P.E

Where, K.E = Kze^2/2r

and P.E = -Kze^2/r

T.E = -Kze^2/2r

so, we can say that

T.E = -K.E

if Total energy given =E

then, K.E must be -E

happy to help!!

:)
Answered by renuhkkohli693
0

Explanation:

option c is the correct answer

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