The total energy of eletcron in the ground state of hydrogen atom is -13.6 eV. The kinetic enegry of an electron in the first excited state is
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Answer: Energy of electron in the first exited state of hydrogen atom is , E = -3.4 eV . Now, we need to find Kinetic and Potential energy of the electron. For , this we should know the relation of total energy between kinetic energy and potential energy . Therefore , K.E = 3.4 eV and P.E = - 6.8 eV .
Explanation:
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