The total energy of the electron in the hydrogen atom in the ground state iz_13.6the KE iz
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by substituiting valrue of constants (n=1)
we get
v at ground state =2.18 x {{10}^{6}} m/s
KE = 1/2mv²
m = 9.1 × 10^-31 kilograms
you will get answer in joules covert it into eV
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