Question

The total horizontal force exerted between the tires of a 1500 kg automobile and the ground is 980 N. If the car starts from rest, how far will it go in 5.0 seconds?

Answer 1

GIVEN:-

• $\rm{Mass\:of\:Automobile=1500kg}$

• $\rm{Force\:exerted\:by\:Ground=980N}$

• $\rm{Time\:Taken=5.0s}$

• $\rm{Initial\:Velocity=0m/s}$

TO FIND:-

• How far the Automobile will travel in 5 Second,after being force applied.

FORMULAE USED:-

• ${\huge{\boxed{\rm{F=ma}}}}$

Where,

F = Force applied

M= Mass

a= Acceleration

• ${\huge{\boxed{\rm{S=ut+\dfrac{1}{2}\times{a}\times{t}^2}}}}$

Where,

S= Distance

u= Initial Velocity

t= Time

a= Acceleration

Now,

Using F= ma,to find Acceleration

$\implies\rm{F=ma}$

$\implies\rm{980=1500\times{a}}$

$\implies\rm{a=\dfrac{\cancel{980}}{\cancel{1500}}}$

$\implies\rm{a=1.53m/s^2}$

Now,

Using Second equation of motion to find out Distance travelled by automobile in 5 s.

$\implies\rm{S=ut+\dfrac{1}{2}\times{a}\times{t}^2}$

$\implies\rm{S=0\times{5}+\dfrac{1}{\cancel{2}}\times{1.53}\times{\cancel{25}}}$

$\implies\rm{S=0+1.53\times{12.5}}$

$\implies\rm{S=0+19.125}$

$\implies\rm{S=19.125m}$

Thus,The Distance travelled by Automobile is 19.125m.

Answer 2

Hi there!

The Answer Of Your Question is 19.125 m.

GIVEN :-

• Force = 980N
• Time = 5s.
• Mass = 1500kg.
• Initial Velocity = 0m/s.

SOLUTION :-

Use Formula :-

$\sf\purple{F = MA}$

Put the values.

$\rm\red{980 = 1500 \times A}$

$\rm\blue{a = 1.53 \: m/ {s}^{2} }$

Now, Use Second Equation of Motion.

$\rm\green{s = ut + \frac{1}{2} a {t}^{2} }$

$\rm\orange{s = 0 + 15.3 \times 12.5}$

$\rm\pink{s = 19.125 \: m}$