The total kinetic energy in joules of the molecules in 8g of methane at 27°c is
Answers
Total kinetic energy = n (3/2 RT0
where n = Number of moles of the gas
R = Gas constant , T = Absolute temperature
Molecular weight of methane, CH 4 = 12 + 4 * 1 = 16
∴ Number of moles of methane in 8.0 gm of methane = 8.0/16.0 = 0.5
R = 8.314 joules/K/mole , T = 27 + 273 = 300 K
∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27 o
C = InI * 3/2 RT = 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
∴ Average kinetic energy = 1870.65/6.023 *10 23 *0.5 =6.21*1021 joules/molecule
Answer:
Explanation:
The total kinetic energy of the 8 g methane molecules is 1,871.58 J.
Explanation:
Temperature of the gas = 27 °C = 300.15 K
Moles of methane gas =
Average Kinetic energy per mole of a gas is given by:
For 0.5 moles of methane, the energy will be:
The total kinetic energy of the 8 g methane molecules is 1,871.58 J.