The total kinetic energy of 1 mole of n2 at 27℃ will be approximately
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Hello!!
¤¤ Kinetic Energy of ideal gas=3/2nRT
¤¤ n=1 mole
¤¤ R=8.314 jk^-1mol^-1
¤¤ T= 27+273 = 300k
¤¤ hence K E = 3/2x1x8.314x300=3741.3 Joule!!
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