Question

The Total Kinetic Energy Of A Body Of Mass 10 Kg And Radius 0.5 M Moving With A Velocity Of 2 M/S Without Slipping Is 32.8 Joule. The Radius Of Gyration Of The Body Is _____.

Answer 1

Answer:

The radius of gyration of the body is 0.4 m

Explanation:

Given data:

Mass = 10 Kg

Radius "r" = 0.5 m

Velocity "v" = 2 m/s

Solution:

The kinetic energy of the particle is given by.

1 / 2mr^2 = mk^2

k=r/√ 2

= 0⋅52 / √2

k = 0⋅35 ~ 0⋅4 m

Thus the radius of gyration of the body is 0.4 m