Question

The total kinetic energy of mass 10kg and radius 0.5 m moving with a velocity’s of 2 m/s without slipping is 32.8joule the radius of gyration of the body is

Answer 1

The radius of gyration of the body is 0.4 m

Explanation:

Given data:

Mass  = 10 Kg

Radius "r" = 0.5 m

Velocity "v" = 2 m/s

Solution:

The kinetic energy of the particle is given by.

1 / 2mr^2 = mk^2

k=r/√ 2

= 0⋅52 / √2

k = 0⋅35 ~ 0⋅4 m

Thus the radius of gyration of the body is 0.4 m

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