Math, asked by vaishnavidounde07, 1 month ago

The total marks obtained by a student in Physics,
for Mathematics together ore 120 more
than the marks obtained by him in Chemistry. What
is the aug, marks obtained by him in Physics &
Mathematics for together?​

Answers

Answered by Barani22
0

Step-by-step explanation:

Let us prepare a chart of the 100 students using the data from the bar graph.

Marks Number of Students

0 − 9 27

10 − 19 12

20 − 29 20

30 − 39 24

40 − 49 17

(i) Number of students with less than 20 marks = 27 + 12 = 39

∴ Required sum to buy the workbooks = Rs. 5 × 39 = Rs. 195

(ii) Highest marks group = 40 − 49

Number of students in this marks group = 17

∴ Required money to distribute the prize = Rs. 10 × 17 = Rs. 170

(iii) Lowest marks group = 0 − 9

Number of students in this marks group = 27

∴ Number of problems that will be solved by the students per day = 5 × 27 = 135

(iv) (a) True

Explanation: Number of students in the marks group 40 − 49 = 17

Total number of students = 100

∴ % of students in the marks group 40 − 49 =17100×100%=17%

(b) False

Number of students in the marks group 10 − 29

= Number of students in the marks group 0 − 9 + Number of students in the marks group 10 − 19

= 12 + 20 = 32

(v) Number of students scoring less than 20 marks

= Number of students in the marks group 0 − 9 + Number of students in the marks group 10 − 19 = 27 + 12 = 39

(vi) Number of students scoring more than 29 marks

= Number of students in the marks group 30 − 39 + Number of students in the marks group 40 − 49 = 24 + 17 = 41

(vii) Number of students scoring between 9 and 40

= Number of students in the marks group 10 − 19

+ Number of students in the marks group 20 − 29

+ Number of students in the marks group 30 − 39

= 12 + 30 + 24 = 56

(viii) The highest marks group is 40 − 49.

Number of students in this marks group = 17

(ix) Number of students scoring more than 19 marks

= Number of students in the marks group 20 − 29

+ Number of students in the marks group 30 − 39

+ Number of students in the marks group 40 − 49

= 20 + 24 + 17 = 61

Answered by prajithnagasai
2

Answer:

Let marks obtained for

Math = x

Physics = y

Chemistry = z

Given, x + y = 120 + z _____(1)

Avg. marks of three subjects

= (x + y + z)/3

= (120 + 2z)/3

= 40 + (2/3)z

Conclusion:

The average marks obtained by the student = 40 + (2/3)z

Similar questions