the total mass of Neutrons in 3.5mg of carbon 14 is
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[Assume that mass of a neutron =1.675×10
−27
kg]search-icon-header
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Find (a) the total number and (b) the total mass of neutrons in 7 mg of
14
C.
[Assume that mass of a neutron =1.675×10
−27
kg]
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Solution
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The number of neutrons is equal to the difference in the mass number and atomic number.
It is equal to 14−6=8.
(a) The number of neutrons present in 7 mg of C-14:
=
14
7×10
−3
×6.02×10
23
×8
=2.408×10
21
neutrons
(b) Total mass of neutrons in 7 mg of C-14:
=2.4088×10
21
×1.675×10
−27
=4.035×10
−6
kg.
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