Question

The total no. of atoms in 8.5 g oh NH3 is

Answer 1

Answer:

heya!

0.5×6.022×10^23 = 3.011×10^23 molecules of NH3. Each NH3 molecule has 4 atoms. Therefore total number of atoms are 3.011×10^23 × 4 =12.044×10^23 atoms.

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Answer 2

The Atomic Weight of the Ammonia is

$(1 \times 14) + (3 \times 1) = 17$

&,17g of ammonia contains 6.022×10^23 of molecules.

Therefore, 8.5g of ammonia contains (8.5/17)×6.022×10^23 molecules or

$(0.5 \times 4 \times 6.022 \times {10}^{23}) = 12.044 \times {10}^{23}$

atoms of Ammonia