Question

The total no. of atoms present in 222g of
Calcium chloride is.​

Answer 1

Answer:

Refer to attachment please.

Answer 2

Given: 222g of calcium chloride.

To find: We have to find the number of atoms.

Solution:

The formula of calcium chloride is $CaCl_2$.

The atomic mass of Ca is 40 and the atomic mass of the Cl atom is 35.5.

Thus, the atomic mass of calcium chloride is

$40 + 35.5 \times 2 \\ 40 + 71 \\ = 111$

Thus 111g of calcium chloride contains $6.023×10^{23}$ number of atoms.

222g of calcium chloride will contain $6.023×10^{23}×2=12.046×10^{23}$ number of atoms.

$12.046×10^{23}$ number of atoms are present in 222g of calcium chloride.