Question

The total no.of electrons in 4.2g of N^3- ion is?

Answer 1

Let Avagadro Number be NA
Nitrogen-Symbol-N -7(atomic number)
N³⁻ ion = 1s²2s²2p⁶
Total number of electrons =10
atomic mass of N=14
14g of N³⁻ ion contains 10NA electrons
where NA - Avagadro number
so, 1 g of N³⁻ ion =10NA/14
∴4.2g of N³⁻ ion =4.2x 10NA/14
=3NA

Here, NA= AVAGAODRO NUMBER

Therefore, answer is 3×6.022×10²³