Question

The total no. Of lone pairs present in xef4

Answer 1

Answer:

here is the answer

total valence electrons are 8+7×4 =36

then divide it by 8

then

36/8 =4+4

then there are 2lone pair because the remainder is 4

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Answer 2

Xe is a noble gas (group 18 element). It has 8 electrons in its outermost orbit/ shell. Fluorine is a halogen (group 17 element). It has 7 electrons in its outermost shell.

Each fluorine atom requires an electron to complete its octet. Thus 4 fluorine atoms require 4 electrons to form four covalent bonds. Xe has 8 electrons in its outermost shell. It shares 4 electrons with 4 F atoms. This way 4 electrons of Xe are used up in bond formation with F whereas its 4 electrons do not participate in bonding, that is, it has 2 lone pairs.

Lone pair means the electron pair which is not used in bond formation...

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