the total no. of moles of O-atom in 16g of SO2 ore
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Here , Given Mass = 16 ( Sixteen ) grams
Molecular Mass = 32 + ( 16 × 2 ) = 64 grams
Now , Number of moles / –
- = Given Mass / Molecular Mass
- = 16 Grams / 64 Grams
- = 0.25 Moles
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Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen .
Now , Number of moles of oxygen in 0.25 Moles of SO² / –
- = 2 × 0.25
- = 0.5 Moles
Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen .
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