Math, asked by anuradha3270, 11 months ago

the total no. of prime factors of 6^5×8^6×12^4×14^2 is​

Answers

Answered by vivek4747
1

Answer:

44

Step-by-step explanation:

(2×3)^5×(2×2×2)^6×(2×2×3)4^×(2×7)^2

=2^5×3^5×2^6×2^6×2^6×2^4×2^4×3^4×2^ 2×7^2

=2^33×3^9×7^2

total no.of prime factors are 33+9+2=44

Similar questions