Question

the total no. of protons present in 72gm of water​

Answer 1

$\huge\pink{\boxed{\mathscr{Solution↓}}}$

Protons present in 18 gram of water = 10(8 of oxygen and 2 of hydrogen)

78g = 78/18 = 4.33

= Take it as 4 moles of water

So , no. Of protons present will be = 4 ×10

=40

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