The total no of valence electron is 4.2g of N3-ions is
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In nitrogen(N) atom having atomic no.7,so electronic configuration = 2,5.
Thus valence e- = 5.Now when it forms N3-ion total no. of valence electrons = 8
Atomic mass of nitrogen = 14
so,
14g N3- ion have valence electrons = 8N (where N = Avogadro’s number)
So, 1g of N3- ion will have valence electrons = 8N/14
therefore,4.2g of N3-ion will have valence electrons = 8N* 4.2/14
= 2.4N
SO,4.2g of N3- ion will have 2.4N valence electrons.
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