the total number of atoms in 4 amu He and 36 amu H2O will be:
Answers
Answered by
5
Answer:
There is 16×6.022×10^23 that is 9.6352×10^24 atoms present in 64amu of helium.
It can be find by calculating the number of moles present in 64amu of helium then multiply it by avogadro number that is 6.022×10^23
Explanation:
Answered by
14
Answer:
7 atoms
Explanation:
No. of atoms of helium= Atomic mass unit/ atomic
mass
= 4amu/ 2= 2 atom of He
No. of molecules of H20 = Atomic mass unit/ atomic mass
= 36 amu/ 18
= 2
since atomic mass of H20 is 1×2 + 16 = 18
Molecules of H20 is 2
therefore atoms in 2H20 is 2*2+ 1*2= 5
total no. of atoms = atom of He+ atom of h20=
5+2=7
therefore atoms are 7
Similar questions