Question

the total number of compression and rarefaction per second in a sound wave is 1000 the frequency of the sound wave is __________​

Answer 1

$\Longrightarrow{\boxed{\bold{Answer:\:1000\:Hz }}}$

$\textbf{\underline{Step-by-step explanation :- }}$

$\small{\bold{Since\:we\:know\:that}} \\ \\ \small{\bold{Frequency = \frac{No.\:of\:compression\:or\:rarefaction}{Total\:Time\:Taken}}}$

$\textsf{\underline{Here, number of compressions}} \\ \textsf{\underline{and rarefaction produced in}} \\ \textsf{\underline{single wave are 1000.}}$

$\textsf{\underline{Therefore, we get frequency}}$

$\bold{\nu = \frac{1000}{1\:s}} \\ \\ \bold{\nu = 1000\:s^{-1}\:or\:1000\:Hz}$

$\bold{\huge{\underline{Note:}}}\\ \\ \mathsf{\underline{\tiny{Frequency\:refers\:to\:number\:of\:waves\:produced\:per\:second}}}$
$\mathsf{\underline{\tiny{Frequency\:is\:denoted\:by\:symbol\:nu\: (\nu) .}}}$

Answer 2

Answer: The frequency of the sound wave is 1000 $s^{-1}$.

Explanation:

Number of compression and rarefaction in 1 second = 1000

Frequency,f=$1000 s^{-1}$

Frequency is the number of oscillation per seconds. In one osculation is composed of 1 compression and 1 rarefaction.

So, the frequency of the sound wave is 1000 $s^{-1}$.