Question

the total number of degrees of freedom for one mole of a diatomic gas at NTP are(N=6.02×10^23/mole)
a)6.02×10^23
b)18.06×10^23
c)30.1×10^23
d)36.12×10^23​

Answer 1

Answer:

total degree of freedom for diatomic gas for 1 molecule=5

Explanation:

2rotational+3 translational

so for 1 mole it will be 6×Na

Answer 2

Answer:

option is C.30.1×10^23