Question

the total number of different orbitals of all the elements present in 6th period is equal to ​

Answer 1

Thus, the number of orbitals here is = 1 + 3 + 5 = 9 (recall that s-subshell has 1 orbital, p-orbital has 3 orbitals, and so on). Since s = ± 1 / 2 , each orbital can fit two electrons, thus total count of electrons is = 2 × 9 = 18 , which is also the total number of elements in the third shell.