The total number of electrons in 1.6 g of CH, to
that in 1.8 g of H2O
(1) Double
(2) Same
(3) Triple
(4) One fourth
please explain
i will mark brainliest ..
Answers
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Hii friend,
Here is your answer...
(1) For H2O..
18g of h2o =6.022 ×10²³ molecules
1.8 g = x molecules
x= 6.022 ×10²² molecules
Total electrons = 8(oxygen) +2(two hydrogen)
Total e— = 10
Total number of e ={x} ×10
= 6.022 ×10²³ electrons......(1)
(2) For CH ,
14 g of CH =6.022 ×10²³ molecules
1.6 g =x molecules
x =1.6 /14 × 6.022 × 10²³
x =0.1142 ×6.022 ×10²³
x =6.882 ×10²² molecules
No. of e– =7 e
Total no. of e =6.882 ×7×10²²
Total no. of e = 4.8174 ×10²³....(2)
This is the total no. of electrons present in both the molecules.
please check the question and options for reference..
Hope this helps you a little!!!
saka82411:
The question is CH4 and not CH
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