Question

the total number of electrons in 1.6g of ch4 to that in 1.8g of h2o

Answer 1

1.6g----CH4
1g CH4 contains 10electron.
then 1.6g contains
1.6*10=16 electrons.
1.8g-----H2O
1g H2O contains 10 electrons
then in 1.8 g contains 18elctrons.
then ratio=16/18=8:9

Answer 2

Molar mass of methane = 16 g
Given mass of methane = 1.6 g
No of moles = 0.1 mol
​No of molecules in 1 mole = 6.022 ×1023 molecules
​No of molecules in 0.1 mole = 6.022 ×1022 molecules
No of electrons in one molecule = (6+1+1+1+1) = 10
No of electrons in 6.022 ×1022 molecules = 6.022 ×1023 electrons


Molar mass of water = 18 g
Given mass of water = 1.8 g
No of moles = 0.1 mol
​No of molecules in 1 mole = 6.022 ×1023 molecules
​No of molecules in 0.1 mole = 6.022 ×1022 molecules
No of electrons in one molecule = (8+1+1) = 10
No of electrons in 6.022 ×1022 molecules = 6.022 ×1023 electrons

Therefore, the total no. of electrons in 1.6gm of methane and that in 1.8 gm of water is same.