Question

the total number of electrons in 18 ml of water with density 1 gm/cm3

:​

Answer 1

mass=p×volume

where p is density

=1×18=18g

$we \: know \: that \: moles = mass \div mol.mass$

moles=18÷18=1mole

$no. \: of \: molecules = no.of \: mole \times 6.023 \times 10 {}^{23}$

=

$= 6.023 \times 10 {}^{23}$

1 molecule of water contains 10 electrons (2of H and 8 of O)

6.023×10^23 molecules will contain

$6.023 \times 10 {}^{24}$

Answer 2

Answer:

18 ml of water contains 18 gm of water implies

1 mole of water. By Avogadro no. 1 mole of

water contains 6.023 x 10^(23) molecules of

water. But each molecule of water contains

10 electrons.

Explanation:

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