Question

the total number of electrons in 2 g of hydrogen is? ​

Answer 1

$\huge\mathbb{\blue{QUESTION-}}$

The total number of electrons in 2 g of hydrogen is ?

$\huge\mathbb{\blue{SOLUTION-}}$

$\large\underline{\underline{\sf Given:}}$

• 2g of Hydrogen

$\large\underline{\underline{\sf To\:Find:}}$

• Total number of electron in 2g of Hydrogen

We know that ➝

❏ 1 mole = 6.023 × 10²³ Atoms

${\sf Moles\:of\:H_2=\dfrac{mass}{molecular\:mass}}$

$\implies{\sf n=\dfrac{2}{2} }$

$\implies{\sf n=1\:mole}$

⛬ Number of Atoms in 2 g of Hydrogen ⎯

$\implies{\sf 2×6.023×10^{23}}$

$\implies{\sf 12.04×10^{23}\:atoms }$

1 Hydrogen atom = 1 electron

⛬ Number of electron in 2g of ${\sf H_2}$ is ${\bf \red{12.04×10^{23}}}$

Answer 2

Answer:

The $2$ grams of hydrogen contains $12.046 * 10^{23}$ electrons.

Explanation:

Concept:

A mole is defined as the quantity of a material that includes precisely $6.023 * 10^{23}$ of the substance's elementary entities. The SI unit of substance amount is the mole, denoted by the sign mol. Exact $6.023 * 10^{23}$ elementary entities make up one mole. The Avogadro number is the fixed numerical representation of the Avogadro constant, NA, when expressed in the unit mol-1.

One mole of any atom contains $6.023 * 10^{23}$ electrons.

Given:

Hydrogen $=2g$

To find:

We have to find the count of electrons in $2g$ of hydrogen.

Solution:

We know that one mole of any atom have $=6.023 * 10^{23}$ electrons

One mole of hydrogen atom $1$ gram of hydrogen $=6.023 * 10^{23}$

Count of moles $=2g$

Therefore, Two moles of hydrogen has,

$=2*6.023 * 10^{23}$

$=12.046*10^{23}$ electrons

Hence, two grams of hydrogen contains $12.046 * 10^{23}$ electrons.

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