Question

The total number of electrons in 4.2 g of N to the power -3 ion is?

Answer 1

Electronic configuration N3- ion = 1s2 2s2 2p6

Atomic mass of N = 14g/mole

Therefore, number of moles of nitride ions in 4.2 g = 4.2/14

  = 0.3 moles

Therefore, number of nitride ions in 0.3 moles = 0.3 x 6.022 x 1023

Number of valence electrons in one nitride ion = 8

So, number of valence electrons in 0.3 x 6.022 x 1023 nitride ions = 8 x 0.3 x 6.022 x 1023

   = 14.45 x 1023

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