Physics, asked by muthusamysfcw, 11 months ago

The total number of electrons in the human body is typically in the order of 10^28. Suppose, due to some reason, you and your friend lost 1% of this number of electrons. Calculate the electrostatic force between you and your friend separated at a distance of 1m. Compare this with your weight. Assume mass of each person is 60 kg and use point charge approximation.

Answers

Answered by abhi178
10

number of electrons in human body = 10^28

charge appeared on my friend and I , C = 1% of charge on 10^28 electrons

= 1/100 × 10^28 × 1.6 × 10^-19 C

= 1.6 × 10^7 C

force between us , Fe = kq²/r²

= 9 × 10^9 × (1.6 × 10^7)²/(1)² [as r = 1m]

= 9 × 2.56 × 10^9 × 10¹⁴

= 23.04 × 10²³ N

= 2.304 × 10²⁴ N

mass on each of us, m = 60kg

so, gravitational force between us, Fg = Gm²/r²

= 6.67 × 10^-11 × 60 × 60/1²

= 6.67 × 36 × 10^-9

= 240.12 × 10^-9

= 2.4012 × 10^-7 N

≈ 2.4 × 10^-7 N

Fe/Fg = 2.304 × 10²⁴/2.4 × 10^-7

= 0.96 × 10³¹ ≈ 10³¹

hence, electrostatic force is approximately 10³¹ times stronger than gravitational force.

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