Question

The total number of electrons present in 16 g of methane gas is

Answer 1

in 16 g methane =1mole =6.022×10^23. molecules

in 1 molecules total electron=6+4=10

so in 1 mole total electron =6.022×10×10^23

=6.022×10^24

Answer 2

6.022×10^24 is the total number of electrons present in 16 g of methane gas.