The total number of electrons present in 16 g of methane gas is
Answers
Answered by
4
in 16 g methane =1mole =6.022×10^23. molecules
in 1 molecules total electron=6+4=10
so in 1 mole total electron =6.022×10×10^23
=6.022×10^24
in 1 molecules total electron=6+4=10
so in 1 mole total electron =6.022×10×10^23
=6.022×10^24
Answered by
1
6.022×10^24 is the total number of electrons present in 16 g of methane gas.
Similar questions