Question

the total number of electrons present in 3.2 g of methane ​

Answer 1

Answer:

19.845 moles of electrons present.

Explanation:

Hope this may help you.....

Answer 2

Explanation:

Molecular formula of methane is CH4.

molecular weight = 12 + 1 × 4

= 12+ 4 = 16amu.

Gram molecular weight = 16 gram

16g of methane = 6.023 × 10^23 molecules

$3.2g \: of \: methane = \frac{6.023 \times {10}^{23} \times 3.2 }{16}$

$= 6.023 \times {10}^{22} \times 2$

$= 12.046 \times {10}^{22} molecules$

Now,Total number of electrons in one molecule of methane = 6 + 1 × 4 = 10

Therefore number of electrons in 3.2g of methane

$= 12.046 \times {10}^{22} \times 10 \\ = 12.046 \times {10}^{23} electrons$