Question

The total number of electrons present in the orbital(s) which have 1 radial node as well as 1 nodal plane for
chromium atom (Z=24) is
(A) 3 (B) 6 (C) 5 (D) 1

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Answer 1

Explanation:

Number of Radial nodes =n−l−1

Given that,

n=4

l=1

No of radial nodes =4−1−1=2

Number of nodal planes = Azimuthal Quantum Number(l)

Since l=1,

Number of nodal planes =1

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Answer 2

Correct option is

B

2,1

Number of Radial nodes =n−l−1

Given that,

n=4

l=1

No of radial nodes =4−1−1=2

Number of nodal planes = Azimuthal Quantum Number(l)

Since l=1,

Number of nodal planes =1

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