Math, asked by priyakunda1074, 7 months ago

The total number of events of throwing ten coins simultaneously is

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Answered by aryagavande
0

now add the cases of 10 coins that is given in above attachment

= 2(1 +10+45+120+210)+252

= 1044 cases

FYI :) this was the Pascal triangle method

I hope this helps please mark me as brainliest

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