Question

The total number of ions persent in 1 mL of 0.1 M
barium nitrate Ba(NO3), solution is -
(1) 6.02 x 10^18
(2) 6.02 x 10^19
(3) 3.0 x6.02 x 10^19 (4) 3.0 x6.02 x 10^18​

Answer 1

Answer:

Option C

Explanation:

Number of moles =molarity×volume

=0.1×0.001

x=10^-4 moles or 0.0001 moles

Ba(NO3)2 ⟶ (Ba^2+) + (NO3^2-)

The total number of ions = 3 ions in one mole of Ba(NO3)2

So, in 10^−4moles = 3×6.023×10^23 ×10^−4

= 3.0×6.02×10^19

Hence, option C is correct.