Question

The total number of ions present in 1 ml of 0.1 M barium nitrate solution

Answer 1

Explanation:

Number of moles =molarity×volume

=0.1×0.001

x=10

−4

moles or 0.0001 moles

Ba(NO

3

)

2

⟶Ba

2+

+NO

3

2−

The total number of ions = 3 ions in one mole of Ba(NO

3

)

2

.

So, in 10

−4

moles = 3×6.023×10

23

×10

−4

= 3.0×6.02×10

19