The total number of ions present in 1 ml of 0.1 m barium nitrate solution is
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Answered by
12
hey
So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is
18.06 * 10^23 = 1.806 * 20^24 ions.
But the concentration is 0.1 Molar, so there are 1.806*10^23 ions in a liter of 0.1 Molar Barium Nitrate
But you want to know the amount in 1/1000 of a liter, so that is
1.806*10^20 ions.
hope u like it
So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is
18.06 * 10^23 = 1.806 * 20^24 ions.
But the concentration is 0.1 Molar, so there are 1.806*10^23 ions in a liter of 0.1 Molar Barium Nitrate
But you want to know the amount in 1/1000 of a liter, so that is
1.806*10^20 ions.
hope u like it
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4
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