Question

The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is140. Then find the number of lions and peacocks in the zoo.

Answer 1

Step-by-step explanation:

Let the number of lions be 'x' and peacocks be 'y'

Given, Total no of lions and peacocks is 50

⇒ x + y = 50

⇒ x = 50 - y eq.[1]

Also, Total no of their legs is 140, as lion has four legs and peacocks has 2 legs

⇒ 4x + 2y = 140

⇒ 4(50 - y) + 2y = 140

⇒ 200 - 4y + 2y = 140

⇒ 2y = 60

⇒ y = 30

Using this in eq.[1]

⇒ x = 50 - 30 = 20

Therefore,

No of lions, x = 20

No of peacocks, y = 30

Answer 2

number of legs

lions x 4

peacock y 2

( x+y=50) ×2

4x + 2 y=140

2x+2y=100

4x+2y=140

-__-____-_____

-2x = -40

x=20

x+y=50

20+y=50

y=30