Math, asked by verma121, 5 months ago

the total number of lions and peacocks in a certain zoo is 50. the total number of their legs is 140. then find the number of lions and peacocks in the zoo. ​

Answers

Answered by ManalBadam
2

\huge\pink{\boxed{Answer↓}}

2.8

\huge\pink{\boxed{Explanation↓}}

total \: animals = 50 \\ total \: legs = 140 \\ so. \: 140 \div 50 \\  = 2.8

Answered by BRAINLYBOT1020
7

\huge  \bigstar \huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}\huge \Rightarrow

  \bold \red{Solution:}\Downarrow

Let there be \large  x lions and \large  y peacocks in the zoo.

From the first condition, \large  x+y=50....(1)

A lion has 4 legs.

Total number of legs of lions = \large  4x

__________________

A peacock has 2 legs.

Total number of legs of peacocks =  \large 2y

From the second condition,

 \large 4x+2y=140

 \large ∴2x+y=70 ... (2)

Subtracting equation (1) from equation (2).

 \large 2x+y=70 ... (2)

\large \underline {x+y=50}. ... (1)

 \large x\:\:=\:\:20

Substituting  \large x=20 in equation (1),

 \large 20 + y = 50  \large y=50-20   y=30

 \large\underline \green{Ans:} \Downarrow

There are 20 lions and 30 peacocks in the zoo.

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