Question

the total number of lions and peacocks in a certain zoo is 50. the total number of their legs is 140. then find the number of lions and peacocks in the zoo. ​

Answer 1

$\huge\pink{\boxed{Answer↓}}$

2.8

$\huge\pink{\boxed{Explanation↓}}$

$total \: animals = 50 \\ total \: legs = 140 \\ so. \: 140 \div 50 \\ = 2.8$

Answer 2

$\huge \bigstar$$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\bold \red{Solution:}\Downarrow$

Let there be $\large x$ lions and $\large y$ peacocks in the zoo.

From the first condition, $\large x+y=50$....(1)

A lion has 4 legs.

∴ Total number of legs of lions = $\large 4x$

__________________

A peacock has 2 legs.

∴ Total number of legs of peacocks = $\large 2y$

From the second condition,

$\large 4x+2y=140$

$\large ∴2x+y=70$ ... (2)

Subtracting equation (1) from equation (2).

$\large 2x+y=70$ ... (2)

$\large \underline {x+y=50}$. ... (1)

$\large x\:\:=\:\:20$

Substituting $\large x=20$ in equation (1),

$\large 20 + y = 50$ ∴ $\large y=50-20$ ∴$y=30$

$\large\underline \green{Ans:} \Downarrow$

There are 20 lions and 30 peacocks in the zoo.