The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is 150.Then find the number of lions and peacocks in the zoo.
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Step-by-step explanation:
Let the number of lions in the zoo be ‘x’ and the number of peacocks be ‘y’. According to the first condition, the total number of lions and peacocks is 50. ∴ x + y = 50 …(i) Lion has 4 legs and Peacock has 2 legs. According to the second condition, the total number of their legs is 140. ∴ 4x + 2y = 140 Dividing both sides by 2, 2x + y = 70 …(ii) Subtracting equation (i) from (ii), Substituting x = 20 in equation (i), x + y = 50 ∴ 20 + y = 50 ∴ y = 50 – 20 = 30 ∴ The number of lions and peacocks in the zoo are 20 and 30 respectively.
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Answer:
probility of no of lions is 35 lions and 75 peacocks
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