Question

The total number of lions and peacocks in a certain zoo is 50. The total number of their
legs is 140. Then find the number of lions and peacocks in the zoo.​

Answer 1

Step-by-step explanation:

Let the number of lion be x and peacock be y

X+Y=50

Lion has 4 legs and peacock has 2 legs,

4x+2y=140

2x+y=70

y=70-2x

Substitute value of y

X+70-2x=50

-x= - 20

x=20

No of lions is 20 and peacock is 30

Answer 2

Given :

The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is 140.

To find :

Find the number of lions and peacocks in the zoo.​

Solution :

Let number of lions be 'x' and number of peacocks be 'y'

1st condition :

⇒ x + y = 50             _(1)

∵ Lion has 4 legs and peacock has 2 legs.

2nd condition :

⇒ 4x + 2y = 140

⇒ 2(2x + y) = 140

⇒ 2x + y = 140/2

⇒ 2x + y = 70              _(2)

Now substracting (1) from (2) :

⇒ 2x + y - x - y = 70 - 50

⇒ x = 20

∴ Number of lions = 20

Now putting value of 'x' in (1) :

⇒ 20 + y = 50

⇒ y = 50 - 20

⇒ y = 30

∴ Number of peacocks = 30.

Therefore,

Number of lions and peacocks are 20 and 30 respectively.