Question

The total number of lions and peacocks in a certain zoo is 50 the total number of their legs is 140 then find the number of lions and peacocks in the zoo.

Answer 1

$\huge{\boxed{\mathbb{ANSWER}}}$

LINEAR EQUATION PROBLEM SOLVING!

Given : The total number of lions and peacocks in a certain zoo

              is 50.

             And the total number of their legs is 140.

To Find : The number of lions and peacocks in the zoo.

Let, us assume that the number of lions be "x"

And the number of  peacocks be "y".

According to the question :-

x + y = 50

x = 50 - y ---- ( 1 )

Therefore, the total number of legs = 140.

So, lion having 4 legs.

And peacock have 2 legs.

According to the question equation will be :-  

4x + 2y = 140

( solving this equation) ( And put the value of "x" in this equation )

{ x  = 50 - y ( eq1 ) }

4(50 - y) + 2y = 140

200 - 4y + 2y = 140

2y = 60

y = 30

∴ The value of y = 30.

Now, from equation ( 1 ) :-

x  = 50 - y ( put the value of "y" here )

x = 50 - 30

x = 20

∴ The value of x  = 20.

ATLAST I AM CONCLUDING WHOLE ANSWER ( final answers ) :-

$\implies \boxed{\mathsf{The\:total\:number\:of\:Lions\:(x)\:=\:20.}}$

And

$\implies \boxed{\mathsf{The\:total\:number\:of\:Peacocks\:(y)\:=\:30 }}$

Answer 2

Given information,

Total No. of Lions and peacocks = 50

Total No. of Legs of Lion and Peacocks = 140

To find: Number of Lions and Peacock and Lions in Zoo

-------- ------- ------------- -----------

Let

Total number of Lions = x

Total number of peacocks = y

By first condition,

x + y = 50 -------- (i)

By second condition,

As we know that,

Lion has 4 legs and peacock has 2

Therefore, 4x + 2y = 140

Dividing 4x + 2y = 140 by 2,

=> 2x + y = 70 ------ (ii)

From equation (i) and (ii)

x + y = 50

2x + y = 70

_____________

3x = 120

x = 120/3

x = 20

Therefore, Total number of Lions in zoo are 20

And, Number of peacocks in zoo = (50-x)

                                                         = 30

Therefore, Total number of peacocks = 30