Question

The total number of men, women and children working in a factory is 18. They earn Rs. 4000 in a day. If the sum of the wages of all men, all women and all children is in the ratio of 18 : 10 : 12 and if the wages of an individual man, woman and child is in the ratio 6 : 5 : 3, then how much a women earn in a day ?
(a) Rs. 500
(b) Rs. 350
(c) Rs. 275
(d) Rs. 250
(e) None of these

Answer 1

Hello

Here is your solution

Given,

Ratio of number of men, women and children=18:10:12

=> (18/6): (10/5):(12/3)

=>3:2:4

=> Total (Men +Women +Children) = 18
3X +2X +4X = 18

=> 9X = 18

=> X = 2

=> Hence, number of women = 2X = 2*2 => 4

Share of all women = (10*4000)/40 = Rs. 1000 [18+10+12 =40]

Thus, share of each woman = 1000/4 = Rs. 250.

=> There option D is the correct answer.............

I hope helps you

Answer 2

Answer:

Basic Method :

Let no. of men , women and children be x , y , z

Given ,

             x+y+z =18   (1)

first divide 4000 in the ratio 9:5:6

wage of all men = 1800

wage of all women = 1000

wage of all children = 1200

Now ,

          Ratio of individual = 6:5:3

          one man = 6k (say)

          one woman = 5k (say)

          one children = 3k (say)

          so,

               6k * x = 1800

               x=300/k

               y=200/k

               z=400/k

  Putting all these value in equation(1)

               k=50

       for one women , wage = 5k = 250rs

So , ANSWER = 250 RS