The total number of moles of lead oxide obtained on thermal
decomposition of 2 mol of lead nitrate is
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Answered by
1
Explanation:
2Pb(NO3)2——∆—-→2PbO+4NO2+O2
On heating Lead Nitrate, two gases Nitrogen dioxide and Oxygen are produced. NO2 gas is a red-brown gas and oxygen is a colourless gas.
So on heating Lead Nitrate decomposes to give 1 mole of colourless Oxygen gas.
But you keep in mind that NO2 dimerises as N2O4, at a lower temperature. So at a lower temperature 2 moles of NO2 will dimerises to give N2O4.
2NO2————->N2O4.
In this case Lead Nitrate will evolve 3 moles on decomposition. You may notice this while heating Lead Nitrate red brown colouration will appear only on strongly heating the salt.
Initially there will be very light red-brown colouration, which deepens on strong heating.
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Answered by
5
Answer:
2Pb(NO3)2——∆—-→2PbO+4NO2+O2
On heating Lead Nitrate, two gases Nitrogen dioxide and Oxygen are produced. NO2 gas is a red-brown gas and oxygen is a colourless gas.
So on heating Lead Nitrate decomposes to give 1 mole of colourless Oxygen gas.
But you keep in mind that NO2 dimerises as N2O4, at a lower temperature. So at a lower temperature 2 moles of NO2 will dimerises to give N2O4.
2NO2————->N2O4.
In this case Lead Nitrate will evolve 3 moles on decomposition. You may notice this while heating Lead Nitrate red brown colouration will appear only on strongly heating the salt.
Initially there will be very light red-brown colouration, which deepens on strong heating.
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