Question

The total number of neutrons present in 54 ml h2o are

Answer 1

Answer:

1.44528×10²⁵ neutrons

Explanation:

Since density of water is almost equal to 1, then 54mL H₂O will have mass of 54g.

No. of moles= given weight/atomic weight

                    =54/18

                    =3

No. of molecules=3×6.022×10²³

                           =18.066×10²³

Total no. of neutrons in H₂O=no. of neutrons of H₂+no. of neutrons of O

                                              =0+8

                                              =8

So, number of neutrons=8×18.066×10²³

                                       =1.44528×10²⁵ neutrons