Question

The total number of orbitals having (n + l) = 4 are:

a) 4

b) 16

c) 32

d) 9

PLZ explain with steps!!
Class 11 Chemistry.

Answer 1

Answer:

Option a) 4

Explanation:

For (n+l) = 4, the following case are possible :-

For n = 4, l = 0

⇒ 4s having 1 orbital in which 2 electrons are present.

For n = 3, l = 1

⇒ 3p having 3 orbitals in which 6 elctrons are present.

For n = 2, l = 2

It is not possible becuase l = n-1 always.

So total there are 4 orbitals and 8 electrons.

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Answer 2

Answer:

4

Explanation:

For (n+l) = 4, the following case are possible :-

For n = 4, l = 0

⇒ 4s having 1 orbital in which 2 electrons are present.

For n = 3, l = 1

⇒ 3p having 3 orbitals in which 6 elctrons are present.

For n = 2, l = 2

It is not possible becuase l = n-1 always.

So total there are 4 orbitals and 8 electrons.

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