Question

the total number of oxygen atoms present in 1.12g quick lime is

Answer 1

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Answer 2

Answer:

The total number of oxygen atoms is $1.2044\times 10^{22}atoms$

Explanation:

Mass of quick lime that calcium oxide = 1.12 g

Molar mass of the quick lime = $\frac{1.12 g}{56 g/mol}=0.02 mol$

Number of molecules of CaO :

$0.02 mol\times 6.022\times 10^{23} mol^{-1}=1.2044\times 10^{22} molecules$

In one molecule of CaO there is 1 oxygen atom , then number of oxygen atoms in $1.2044\times 10^{22} molecules$ are:

$1\times 1.2044\times 10^{22} =1.2044\times 10^{22} atoms$

The total number of oxygen atoms is $1.2044\times 10^{22} atoms$