The total number of protons in 10 g of calcium carbonate is
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molecular mass of CaCO3=40+12+16*3=100g
No. of molecules in 100g CaCO3=6.022*10^23molecules
No. of molecules in 10g CaCO3=((6.022*10^23)/100)*10=6.022*10^22 molecules
No. of protons in 1 molecule of CaCO3=20+6+3(8)=50
No. of protons in 6.022*10^22molecules=50*6.022*10^22protons=301.1*10^22protons=3.011*10^24protons
No. of molecules in 100g CaCO3=6.022*10^23molecules
No. of molecules in 10g CaCO3=((6.022*10^23)/100)*10=6.022*10^22 molecules
No. of protons in 1 molecule of CaCO3=20+6+3(8)=50
No. of protons in 6.022*10^22molecules=50*6.022*10^22protons=301.1*10^22protons=3.011*10^24protons
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