The total number of protons in 10g of caco3 is
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Answer:
Explanation:
The molecular mass of CaCO3=100gmol−1
No. of moles, n=mM=10g100gmol−1=0.1mol
That means there are 0.1⋅6.022⋅1023=0.6022⋅1023=6⋅1022 molecules in 10g.
No. of
Ca atoms in a molecule=1
C atoms in a molecule=1
O atoms in a molecule=3
Total atoms in a molecule=5
Now it's to do with protons. In a molecule of CaCO3 , there are protons
Protons of a Ca atom=20
Protons of a C atom=6
Protons of a O atom=8
Total no. of protons in a molecule=20×1+6×1+8×3=50
So, the total no. of protons in 10g:
no. of protons = 50×6×1022=3×102×1022=3×1024
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