The total number of terms in the expansion of (x+a)100+(xa)100 after simplification will be
Answers
Answered by
1
Nice question my friend
Answered by
1
(a+b)n=nC0an+nC1an−1b1+nC2an−2b2+.....nCran−rbr+nCnbn
(x+a)100+(x−a)100
2[100C0x100a0+100C2x98a2+.....+100C100x0a100]
⇒2x100+2100C2x98a2+....2a100
Hence there are 51 terms.
Similar questions