The total number of valence electrons in 4.2 g of N^-3 ion is (NA is the Avogadro's number)
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No.of ions in 0.3 moles is 0.3*N no of nitride ions. Nitride ion is a stable ion, meaning it has 8 valence electrons. The no of moles of nitride ion in 4.2g is 4.2/14=0.3 mol. So the no of valence electrons is equal to 8x0.3xNa, where Na is avogadros no. whose value is (6.022x10^23).
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17
42g of N3-contains no of e-= 16
4.2g contains=16x4.2/42
=1.6 valence electrons
Suryha:
Can I know why did u add 1 to the no.of e-
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