Math, asked by sumant98, 11 months ago

The total number of ways in which 10 different toys can be distributed among three different children, so that the first gets 5, the second gets 3 and
third gets 2, is​

Answers

Answered by 12Aalok34
0

The total number of ways in which 10 different toys can be distributed among three different children, so that the first gets 5, the second gets 3 and

third gets 2, is 1.

sumant98: ans?
sumant98: ans?
12Aalok34: 1 because it can be only written in one way
sumant98: this is not a ans..
12Aalok34: then what is correct answer zero or three
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